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Question #b5f73 - Socratic Then, we can just find the mass of 2 272 carbon atoms by multiplying 2 272 by the mass of 1 mole of carbon: 2 272 xx 12 01 = "27 29g" Since there was 1 significant figure in the question, our answer is "30g" Another way to solve this problem is by using the mass percent!
1545 subjects were given ginko 1524 placebo. In ginko . . . - Socratic 1545 subjects were given ginko 1524 placebo In ginko group, 246 developed dementian in the placebo it was 277 with dementia Significance level=0 01 to test claim (ginko is effective in dementia) Can you test claim and construct confidence interval? Statistics
Question #6f7d1 - Socratic 675N Here,the kinetic energy of the hammer head got totally converted to the work done in moving the nail through a distance of 10 mm or 0 01 m So, kinetic energy of the hammer during the strike was 1 2 m v^2=1 2×1 5×3^2=6 75J Now,if an average force of F had acted on the nail to move it by 0 01 m,then work done by the force will be (F×0 01)J(using W=F*s) So,we can equate both 6 75=F×0 01
Question #18488 - Socratic The degree of dissociation sf (alpha=0 0158) sf (K_b=2 51xx10^ (-6)color (white) (x)"mol l") Triethyamine is a weak base and ionises: sf ( (CH_3)_3N+H
Question #fe281 - Socratic 4 ⋅ 12 01 = 48 04 g We now know that one mole of carbon contains 48 04 grams of carbon Next, we determine how many grams of carbon are in one mole of CO 1 ⋅ 12 01 = 12 01 g Now, we know that one mole of CO contains 12 01 grams of carbon With this information, we can determine how many moles of CO can be formed with the given mass of C
How many molecules of N_2O_3 are present in 28. 3 g of N_2O_3? - Socratic 2 228 × 10^"23" molecules 1 mole contains 6 022140857 × 10^"23" (Avogadro's number) The molecular weight of N_2O_3 is: 76 01 g mol You have 28 3 g, so you have 28 3 76 01 = 0 37 mole Hence you have 0 37 × 6 022140857 × 10^"23" = 2 228 × 10^"23" You have 2 228 × 10^"23" molecules
How do you use the important points to sketch the graph of # . . . - Socratic Please see the explanation below The equation is y=2x^2+2 Compare this equation to y=ax^2+bx+c The coefficient of x^2 is a=2 >0 So the curve is convex Now, calculate the intercepts with the y-axis x=0, =>, y=2 So a point is (0,2) Now, calculate the intercepts with the x-axis y=0, =>, 2x^2+2=0 =>, x^2+1=0 x^2=-1 There are no intercepts with the x-axis When x=-x, the curve does not change The
Question #94c52 - Socratic Using the isotopic masses and their relative abundance, the average atomic mass comes out to 24 3051 u You work this out as a weighted average Each isotope's mass is multiplied by its relative abundance, and the products are then added together to give the average atomic mass Here are the details: (23 9850 xx 0 7899)+(24 9858xx0 100)+(25 9826xx0 1101) Note that I have taken the liberty to