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Use the difference quotient to estimate the instantaneous . . . - Socratic See below f (x) =x^2 Let f' (3) = the instantaneous rate of change in f (x) at x=3 To estimate f' (3) we can use the difference quotient: (f (x+deltax)-f (x)) (deltax) for x=3 and some small deltax Let's choose deltax = 0 01 Then, f' (3) approx ( (3+0 01)^2- 3^2) 0 01 approx (9 0601-9) 0 01 approx 6 01 Now let's find f' (x) as deltax ->0 f' (x) = lim_ (deltax->0) (f (x+deltax)-f (x)) (deltax
How do you convert the angle - Socratic Conversion table of degrees, minutes and seconds 60sec = 1 min,60 min −1degree ∴ 1degree = 60⋅ 60 = 3600sec 135∘36” ⇒ 135∘ +0’ +36” = 135 + (36 60 ⋅ 60) ⇒ 135 +(361 3600100) = 135(1 100) = 135 01∘
What is the Celsius temperature scale? - Socratic The triple point temperature of water is exactly 0 01 °C The difference between these two temperatures is 273 16 °C A Celsius degree is exactly 1 273 16 of this difference This definition keeps the freezing point of water at exactly 0 °C and the boiling point of water at exactly 100 °C
How do you graph the ellipse (x+5)^2 16+ (y-4)^2 1=1 and . . . - Socratic Please see below (x-h)^2 a^2+ (y-k)^2 b^2=1 is the equation of an ellipse, whose center is (h,k), 2a and 2b are major axis and minor axis (if a>b, but if a< b, it is reverse) In the former case major axis is parallel to x-axis and in latter case major axis is parallel to minor axis vertices are (h,k+-b) and (h+-a,k) Eccentricity e can be obtained using e=sqrt (1- ("minor axis")^2 ("major
Question #e2e8b - Socratic The percent composition is the percent breakdown of the relative element masses in the molar mass (gram formula mass) of a given molecular formula The percent composition of water can be found by first finding the molar mass of water Water has a ratio of two atoms of hydrogen for every one atom of oxygen H_2O hydrogen has a mass of 1 01 amu oxygen has a mass of 15 99 amu H 2 x 1 01 = 2 02 O
How many grams of N_2 are required to completely react with . . . - Socratic 7 01"g" Notice the coefficients of N_2 and H_2 Since the equation has an N_2 and 3H_2, 3 times as many moles of H_2 will be used as N_2 assuming a complete reaction Since we're given the mass of H_2 being used, we can divide that by the molar mass of H_2 to determine how many moles of H_2 will be consumed