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SUN

GRANDE PRAIRIE-Canada

Company Name:
Corporate Name:
SUN
Company Title:  
Company Description:  
Keywords to Search:  
Company Address: 9835 101 Ave #200,GRANDE PRAIRIE,AB,Canada 
ZIP Code:
Postal Code:
T8V5V4 
Telephone Number: 7805399700 
Fax Number: 7805321600 
Website:
 
Email:
 
USA SIC Code(Standard Industrial Classification Code):
483201 
USA SIC Description:
Radio Stations & Broadcasting Companies 
Number of Employees:
20 to 49 
Sales Amount:
$2.5 to 5 million 
Credit History:
Credit Report:
Excellent 
Contact Person:
Tom Bedore 
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Company News:
  • How much lux does the Sun emit? - Physics Stack Exchange
    If you want your eyes to receive 32000~100000lux, you need to stare at the sun in a sunny day If you stare at the ground in a sun-exposure area, your eyes receives much less than 32000 lux If you stare at a shedded ground in a sunny day, your eyes receive slight less than 10000lux human eyes could not tolerate 32000lux more than 5 secounds
  • everyday life - Why do sunbeams diverge even though the sun is much . . .
    The same applies to the beams of light above them The Sun is very far away and the beams are pretty much parallel, but they're pointing towards you, and perspective makes them appear to converge towards the vanishing point - which in this case is the Sun's location in the sky The technical term for these beams is "crepuscular rays "
  • How is distance between sun and earth calculated?
    Another way of calculating the earth - sun distance is to look at the centrifugal and the gravitational force This solution assumes that one already knows the mass of the sun, but thats a different problem ;-)
  • sun - Why is sunlight spectrum continuous? - Physics Stack Exchange
    The continuous spectrum of the visible photosphere of the Sun is attributable to the radiative equilibrium of the $\mathrm{H}^{-}$ ion This has been recognised for at least 80 years ( Wildt 1939 ) This ion forms by the attachment of a free electron (with a continuous spectrum of energies) to a hydrogen atom, emitting a continuous spectrum of
  • How does the Earths orbit change as the Sun decreases in mass?
    Now the Sun loses a small amount of mass The Earth is still traveling at the same velocity, and requires the same centripetal force to maintain the same circular orbit Unfortunately, the reduced mass of the Sun no longer supplies the required centripetal force So the Earth is now in a slightly elliptical orbit, passing perihelion
  • astronomy - How big a coincidence is the Sun and Moon having almost . . .
    Note that every moon with diameter i will block the sun in 201-i different orbits The smallest moon will block the sun in only one orbit, LEO The probability of a moon 2000 miles in diameter is thus $\frac{1}{200^2}$ that of the smallest moon Then the probability that a moon will block the sun is:
  • How hot can metal get in sunlight? - Physics Stack Exchange
    Stefan-Boltzmann: J = σT4 J = σ T 4 To lose 1 kW over 1 m 2 requires a temperature of T = 1000 5 67 ⋅10−8− −−−−−−−−√4 ≈ 364 K T = 1000 5 67 ⋅ 10 − 8 4 ≈ 364 K This assumes only the surface facing the sun loses heat by radiation: in other words this is only valid for a black surface mounted on a good insulator
  • What is actually meant by sun set and sun rise times, when taking . . .
    The Sun has actually set risen and we see it due to the way light is bent across the atmosphere Apparently due to coincidence of the size and distance of the sun, its exactly the same size - so if we see 50% of the sun, the sun is 50% below the horizon So, I understand all this, so here is my question :
  • What does the Moons orbit around the Sun look like?
    This is easily proven by comparing the minimum possible gravitational acceleration of the Moon toward the Sun (5 7 mm s 2) and the maximum possible gravitational acceleration of the Moon toward the Earth (3 1 mm s 2) The acceleration vector, and hence the curvature, is always inward This means the Moon's orbit about the Sun doesn't look like
  • How to calculate the Sun’s energy output? [closed]
    So, now you need to simply calculate the total power passing through a sphere whose radius is the same of the Earth's orbit, and this is P = 4πR2F ≈ 3 8 ×1026W = 3 8 ×1026J s P = 4 π R 2 F ≈ 3 8 × 10 26 W = 3 8 × 10 26 J s Since energy is conserved this number is the amount of power passing through any surface surrounding the Sun




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