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power series - How can we know the answer to 1-1+1-1+1 . . . There are multiple measures of what that comes to but intuitively you might think that the value alternates between 1 and 0, so you could call it a half In truth this series never converges on any given number Depending on how you define addition, the sum to infinity is not properly defined You might argue that the sum of those numbers is 1 if $\infty$ is an odd number and $0$ if $\infty
abstract algebra - Prove that 1+1=2 - Mathematics Stack Exchange Possible Duplicate: How do I convince someone that $1+1=2$ may not necessarily be true? I once read that some mathematicians provided a very length proof of $1+1=2$ Can you think of some way to
Why is $1 i$ equal to $-i$? - Mathematics Stack Exchange 11 There are multiple ways of writing out a given complex number, or a number in general Usually we reduce things to the "simplest" terms for display -- saying $0$ is a lot cleaner than saying $1-1$ for example The complex numbers are a field This means that every non-$0$ element has a multiplicative inverse, and that inverse is unique
一 (一) 1 （1）1） ① 是这个顺序吗 写公务文件_百度知道 一 (一) 1 （1）1） ① 是这个顺序吗 写公务文件文章中正确使用序号的顺序如下：第一层为“一、二、三”第二层为”（一） （二） （三）“第三层为1 2 3第四层为（1）（2）（3）第五层为①②③扩展资料：1、阿拉伯数
General term formula of series 1 1 + 1 2 + 1 3 . . . +1 n You'll need to complete a few actions and gain 15 reputation points before being able to upvote Upvoting indicates when questions and answers are useful What's reputation and how do I get it? Instead, you can save this post to reference later
What is the value of $1^i$? - Mathematics Stack Exchange First, a concrete example of things that can happen with complex exponentiation if you aren't careful: $1 = e^ {2\pi i}$, so we can naively try to compute $1^i = (e^ {2\pi i})^i = e^ { (2\pi i)i} = e^ {-2\pi}$ The formal moral of that example is that the value of $1^i$ depends on the branch of the complex logarithm that you use to compute the power You may already know that $1=e^ {0+2ki\pi