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Difference between: Opcode, byte code, mnemonics, machine code and . . . OPCODE: It is a number interpreted by your machine (virtual or silicon) that represents the operation to perform BYTECODE: Same as machine code, except, its mostly used by a software based interpreter (like Java or CLR) MNEMONIC: English word MNEMONIC means "A device such as a pattern of letters, ideas, or associations that assists in remembering something " So, its usually used by assembly
assembly - Intel x86 Opcode Reference? - Stack Overflow What is a relatively quick and easy method of looking up what an arbitrary opcode means (say, 0xC8) in x86? The Intel Software Developer's manual isn't very fun to search through
assembly - How does an instruction decoder tell the difference between . . . The decoder is a state machine It knows where the instruction starts, the prefixes' values, and that prefixes are optional and that they come first One-byte opcodes don't overlap with prefixes, two and three bytes opcodes start with 0f which is not a prefix So the decoder can tell when the opcode starts Alas, Intel reused the prefixes to change meaning to opcodes The decoder takes that
What is the difference between Mnemonics and Opcode Usually opcode refers to the type of operation (ADD), and register B is an operand However, with a fixed and small number of operands, the same operation can have different opcode for all possible operands
What is the difference between machine code and opcode? The question is mostly related to PHP because IMHO opcode is mostly mentioned in PHP context According to this description, here's a transformation process of php code into opcode: php text ->
How is machine code stored in the EXE file? - Stack Overflow Note that an opcode is only part of the machine code bytes or bits for a single instruction The rest of the bits encode the operands, if there are any operands that aren't implicit (In some circles, "opcode" is misused to describe whole machine code instructions, so that's probably where the misuse of terminology in this question came from )
assembly - Calculate the JMP opcodes - Stack Overflow The formula is correct, assuming the jump instruction has exactly 5 bytes and FROM is the address of this jump instruction If the length isn't 5 or FROM isn't where jmp is, it's incorrect With that you get in modulo 2 32 arithmetic: 2980000H- (6259326BH+5)=0A03ECD90H If you don't understand how 2980000H - 62593270H equals 0A03ECD90H in 32 bits, imagine for a moment that you're subtracting
Reading file input as opcode in C++ - Stack Overflow I am working on a project for a class at school It is a simple implementation of stacks and queues However as part of the project we are require to read opcode in from a file The opcode is forma