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Regular expression to stop at first match - Stack Overflow to capture a match between start and the first occurrence of end Notice how the subexpression with nested parentheses spells out a number of alternatives which between them allow e only if it isn't followed by nd and so forth, and also take care to cover the empty string as one alternative which doesn't match whatever is disallowed at that
OR condition in Regex - Stack Overflow For example, ab|de would match either side of the expression However, for something like your case you might want to use the ? quantifier, which will match the previous expression exactly 0 or 1 times (1 times preferred; i e it's a "greedy" match) Another (probably more relyable) alternative would be using a custom character group:
Regular expression to match string starting with a specific word How do I create a regular expression to match a word at the beginning of a string? We are looking to match stop at the beginning of a string and anything can follow it For example, the expression
XSL: Meaning of `match= ` for `xsl:template` - Stack Overflow The value of the match attribute of the <xsl:template> instruction must be a match pattern Match patterns form a subset of the set of all possible XPath expressions The first, natural, limitation is that a match pattern must select a set of nodes There are also other limitations In particular, reverse axes are not allowed in the location steps (but can be specified within the predicates
regex - What do lazy and greedy mean in the context of regular . . . Taken From www regular-expressions info : Greedy quantifiers first tries to repeat the token as many times as possible, and gradually gives up matches as the engine backtracks to find an overall match : Lazy quantifier first repeats the token as few times as required, and gradually expands the match as the engine backtracks through the regex to find an overall match
Regex how to match an optional character - Stack Overflow I have a regex that I thought was working correctly until now I need to match on an optional character It may be there or it may not Here are two strings The top string is matched while the lo