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Whats the difference between %ul and %lu C format specifiers? But using %lu solved the issue Actually, rather than focusing on the problem and the line of codes, I want to know about the difference between %ul and %lu Maybe I could figure out what's wrong Searching doesn't give me something useful (except that "they are different") Any explanation or link reference is appreciated
How to printf unsigned long in C? - Stack Overflow @Anisha Kaul: %lu is a valid conversion specification, %ul is not %lu, broken out is: % — starts a "conversion specification"; l — the length modifier, l means " [unsigned] long int"; u — the conversion specifier, u is for an unsigned int to be printed out as decimal Because we gave the length modifier l, it then accepts an unsigned long int The letters must be in that order: percent
printf - Difference between %zu and %lu in C - Stack Overflow 11 What is the difference between %zu and %lu in string formatting in C? %lu is used for unsigned long values and %zu is used for size_t values, but in practice, size_t is just an unsigned long CppCheck complains about it, but both work for both types in my experience
LU decomposition error in statsmodels ARIMA model import numpy as np from statsmodels tsa arima model import ARIMA items = np log(og_items) items['count'] = items['count'] apply(lambda x: 0 if math isnan(x) or math isinf(x) else x) model = ARIMA(items, order=(14, 0, 7)) trained = model fit() items is a dataframe containing a date index and a single column, count I apply the lambda on the second line because some counts can be 0, resulting in
Why do I get %lu when I try to print a u64 variable with %llu . . . When I print the number using the format specifier "%llu", what is printed is "%lu" I also compare the value I get from atoll or strtoll with the expected value and it is smaller, which I guess shows that an overflow has occurred Why does an overflow occur if the number fits in a u64 variable? The number for example is 946688831000