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Whats the difference between %ul and %lu C format specifiers? But using %lu solved the issue Actually, rather than focusing on the problem and the line of codes, I want to know about the difference between %ul and %lu Maybe I could figure out what's wrong Searching doesn't give me something useful (except that "they are different") Any explanation or link reference is appreciated
printf - Difference between %zu and %lu in C - Stack Overflow What is the difference between %zu and %lu in string formatting in C? %lu is used for unsigned long values and %zu is used for size_t values, but in practice, size_t is just an unsigned long
How to printf unsigned long in C? - Stack Overflow @Anisha Kaul: %lu is a valid conversion specification, %ul is not %lu, broken out is: % — starts a "conversion specification"; l — the length modifier, l means " [unsigned] long int"; u — the conversion specifier, u is for an unsigned int to be printed out as decimal Because we gave the length modifier l, it then accepts an unsigned long int The letters must be in that order: percent
c++ - printf and %llu vs %lu on OS X - Stack Overflow Possible Duplicate: how to printf uint64_t? Why is it that on my 64-bit Mac (I am using Clang) the uint64_t type is unsigned long long while on 64-bit Ubuntu the uint64_t type is unsigned long?
LU decomposition error in statsmodels ARIMA model import numpy as np from statsmodels tsa arima model import ARIMA items = np log(og_items) items['count'] = items['count'] apply(lambda x: 0 if math isnan(x) or math isinf(x) else x) model = ARIMA(items, order=(14, 0, 7)) trained = model fit() items is a dataframe containing a date index and a single column, count I apply the lambda on the second line because some counts can be 0, resulting in
Why is sprintf with a %llu returning the letters lu? Instead, I get timestringLength == 2 and my buffer has the letters lu on top I don't know how this is happening I have build flags in Eclipse CDT for -std=c99, so it's not a c90 issue I tried with long long unsigned instead of uint64_t STM32CubeMxIDE (Eclipse v20210303, CDT 10 x), GCC, built for c99
To find an inverse matrix of A with LU decomposition The task asks me to generate A matrix with 50 columns and 50 rows with a random library of seed 1007092020 in the range [0,1] import numpy as np np random seed(1007092020) A = np random randint(2,
Why do I get %lu when I try to print a u64 variable with %llu . . . When I print the number using the format specifier "%llu", what is printed is "%lu" I also compare the value I get from atoll or strtoll with the expected value and it is smaller, which I guess shows that an overflow has occurred Why does an overflow occur if the number fits in a u64 variable? The number for example is 946688831000
c - Is it valid to use %lu in a format string for printf where PRIu32 . . . printf("%lu\n", i); I’d suppose yes, since I can see no reason why not However, if yes, then this would remove the need for existence of these macroified specifiers like PRIu32, so I figure I’d better ask The reason I’m asking it is that I’d like to create a format string for printf dynamically, and it’d be hard to allocate space for this format string if I don't know the size of