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K & L
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K & L
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Company Address:
1429 Us Highway 22,MOUNTAINSIDE,NJ,USA
ZIP Code: Postal Code:
07092-2406
Telephone Number:
9086547037 (+1-908-654-7037)
Fax Number:
9086545921 (+1-908-654-5921)
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USA SIC Code(Standard Industrial Classification Code):
738913
USA SIC Description:
Appraisers
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Company News:
differential geometry - $ (k,l)$ shuffle and wedge product . . . Note you have a few typos You typed $\binom {k+1}k$ instead of $\binom {k+l}k$ and then the symbol upside-down
Algebraic proof of complex locus of circle $k|z-z_1|=l|z-z_2|$ I read that more as a hint than a requirement What you are asked to prove is essentially $\left| z - \frac {k^ {2}z_ {1}-l^ {2}z_ {2}} {k^ {2}-l^ {2}} \right
field theory - How to prove $\mathrm {Gal} (K LM)=\mathrm {Gal} (K L . . . An automorphism is in $\Gal (K L)\cap\Gal (K M)$ iff it fixes all elements of $L$ and all elements of $M$ Now why must an automorphism fixing all elements of $M$ and of $L$ also fix all elements of $LM$ and vice versa?
if $ (k+m)^n + (l+m)^n = (k+l+m)^n$ then $kl$ divides $m^n$ I am impressed! A very clear-cut use of the binomial theorem The inner $l^j$ and $k^j$ cancel out Thank you very much
What does the notation {i, j} ∩ {k, l} = ∅ mean? should {i,j} be edge . . . What does the notation {i, j} ∩ {k, l} = ∅ mean? should {i,j} be edge? Please give some hint so I can start working on the question Ask Question Asked 8 years, 9 months ago Modified 8 years, 9 months ago
differential geometry - Contraction of a tensor over all indexes . . . Most likely your product tensor should be of type $T_ {k+l}^ {k+l}$ and the contraction is really just evaluation of $F$ on the $w$'s and the $X$'s (you are not contracting $w$'s against the $X$'s)
Prove that $ (a+b\sqrt {2})^n $ is of the form $k+l\sqrt {2}$ where $a . . . If $ (a + b\sqrt {2})^ {n} = k + l\sqrt {2}$ for some integers $k$ and $l$, then multiplying the equation by $a + b\sqrt {2}$, you get $$ (a + b\sqrt {2})^ {n+1} = (ak + 2bl) + (bk + al)\sqrt {2} $$
Let $K$ be a Galois extension of $F$ with $ [K F] = n$. If $p$ is a . . . Is easy show that $\mathrm {Gal} (K F)$ has a subgroup $H$ of order $p$ and so, the Fundamental Theorem of Galois Theory says that any subfield $L$ such that $H \longleftrightarrow L$, satisfies $ [K:L] = p$
Construct Context-Free Grammar for $\ {a^ib^jc^kd^l : i,j,k,l\geq1 . . . Unfortunately, this doesn't help me much, I've never heard of such a thing as context-free grammar of intersection I just don't understand how I'm supposed to meet the condition that the total number of a and b is equal to the total number of c and d because that's what it comes down to
Showing that the Lah numbers satisfy $L(n + 1, k) = (n + k)L(n, k) + L . . . The second summand is (n + k)L(n, k) (n + k) L (n, k) once you notice that such an ordered partition arises by creating an ordered partition of [n] [n] into k k parts and then placing n + 1 n + 1 into one of n + k n + k spots