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How would you balance HCI + NaOH -- gt;H20 + NaCI? - Socratic Well in fact you have already balanced this In every chemical reaction, mass is conserved, and it is conserved in the acid base reaction above If there are 5 g of reactant there must be 5 g of product This is an example of stoichiometry To put this in another context, suppose you went to a shop with a £20-00 note, and made a purchase worth £8-15 If you received £5-85 in change, would
What is the balanced chemical equation of Ca2 +H2O gt;C2H2 - Socratic I think you mean CaC_2 rather than Ca_2, otherwise where is the C atom in the product coming from?! This is the reaction between calcium carbide and water, which produces ethyne, (old name acetylene) which is highly flammable To balance the equation, firstly look at the carbon atoms We have 2 in the CaC_2 and 2 in the C_2H_2, so we can see that they have 1:1 stoichiometry Now look at the
How would you balance the following equation: Fe + Cl2 + H2O . . . - Socratic You are oxidizing iron, and then making a coordination complex I will give you a reaction scheme OXIDATION Fe(s) + 3 2Cl_2(g) rarr FeCl_3(s) COMPLEXATION FeCl_3(s) + 6H_2O(l) rarr [Fe(OH_2)_6]^(3+)(Cl^-)_3 I don't know whether this is completely what you want
How do you balance and translate this reaction: - Socratic If we combine these we can obtain 1mole of H2O #Ca(OH)_2 + H_2SO_4 = 2H_2O + CaSO4# Now you can write down the ionic reaction #Ca^(2+) + 2OH^(-) + 2H^(+) + SO4^(2-) = 2H_2O+ Ca^(2+) + SO4^(2-)# (I know that SO4^-2 is confusing So I recommend you that to determine the charge of an ion Use the zero sum rule )
What is the enthalpy for the reaction Ca(OH)2 (s) - Socratic Unknown We would predict it to be negative Ca(OH)_2(s) + CO_2(g) rarr CaCO_3(s)darr + H_2O(l) The formation of solid calcium carbonate is a bond forming reaction A solid precipitate of calcium carbonate occurs We would thus predict the enthalpy of the reaction to be negative To give numbers we need experimental data
How many grams of water are produced when propane (C3H8 . . . - Socratic 7 72 "g H"_2"O" The NIE for the complete combustion of propane is: "C"_3 "H"_8 + 5 "O"_2 -> 3 "CO"_2 + 4 "H"_2"O" The problem doesn't state how much propane is burned, so we're going to assume that there is enough to use up all the oxygen To find out how much that is, we need to convert liters of "O"_2 to moles of "O"_2 using the fact that at STP, a mole of gas is equivalent to 22 4 liters
The overall reaction in the body is described by the equation C6H12O6 . . . Approx 25*g with respect to oxygen You have the stoichiometric equation C_6H_12O_6(g) +6O_2(g) rarr 6CO_2(g) + 6H_2O(l) And the normal rigmarole in these reactions, is to balance the carbons as carbon dioxide, then balance the hydrogens as water, and THEN balance the oxygens