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9 8 7 6 5 4 3 2 1 = 0 and 1 2 3 4 5 6 7 8 9 = 0 - Puzzling Stack Exchange AND do the same for Reverse order 9 8 7 6 5 4 3 2 1 = 0 Your answers must represent all the digits in sequence All digits must appear once Only + - x ! allowed Parentheses are counted as though they were operations; each pair of parentheses is 2 operations Every sign introduced is a step No partial answers I expect more than one solutions
10 9 8 7 6 5 4 3 2 1 = 2016 - Puzzling Stack Exchange 10 9 8 7 6 5 4 3 2 1 10 9 8 7 6 5 4 3 2 1 To get the total 2016 2016 Rules: We are looking for the simplest solution - i e the least amount of characters (ignoring spaces) Please include your character count in your answer Keep the order; do not add or combine numbers Use all four operators at least once Credit for initial concept: Alex
10 9 8 7 6 5 4 3 2 1 = 2017 - Puzzling Stack Exchange 10 9 8 7 6 5 4 3 2 1 10 9 8 7 6 5 4 3 2 1 To get the total 2017 2017 Rules: Look for the simplest solution - i e the least amount of characters (ignoring spaces) Please include your character count in your answer Keep the order; do not add or combine numbers Use all four operators at least once Credit for initial concept: Alex Bellos
1 2 3 4 5 6 7 8 9 = 100 - Puzzling Stack Exchange The sequence of numbers $1\ 2\ 3\ 4\ 5\ 6\ 7\ 8\ 9$ has the property that you can insert mathematical operators in between the numbers from $1$ to $9$ and make the expression evaluate to 100 For e
Create all numbers from 0-100 only using all of 1,2,3,4 and 5 Create all numbers from 0-100 only using 1,2,3,4 and 5 No repeats and you have to use each number Also, you can use any operation I've only gotten to 50 by pure brute force I think that this mi
mathematics - Make 6 5 4 3 = 81 - Puzzling Stack Exchange Can you find a way to make: 6 5 4 3 = 81 by concatenation and or adding any of (and only) these mathematical operators: + - × ! ÷ ^ standard parentheses () You cannot add other numbers to the equ
Expressing numbers using 0, 1, 2, 3, and 4 - Puzzling Stack Exchange 6 The least number that cannot be written using the numbers 0, 1, 2, and 3, each exactly once, and any combination of standard arithmetic operations (including factorials) is 41 What is the least such number if the numbers 0, 1, 2, 3, and 4 are allowed?
Can you make 39 using the numbers 5 4 3 2 1 in that order? -10 Is it mathematically possible to show by some creative way that when you combine the digits 5, 4, 3, 2, 1 in that order using operators (+, -, x, integer division floating point division ( ) or modulus (%)) that you will or will not get the number 39? By adding other operators it's possible: