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Conditions of Bernoullis equation: Do they matter? Bernoulli's equation: P + 1 2ρv2 + ρgh = constant P + 1 2 ρ v 2 + ρ g h = constant There are some conditions to use Bernoulli's equation But often we neglect them The fluid must be incompressible But we use this equation in many cases where the fluid is air, such as to find the lifting force on the wings of an airplane (image below), to describe how a hurricane rips a roof of a house
What is the term $P$ in bernoullis equation defined as? 1 2ρv2 + ρgh + p = C 1 2 ρ v 2 + ρ g h + p = C What is the term 𝑃 in bernoulli's equation defined as? Pressure energy because work is ⋅ ⋅ so there must be a change of volume of the fluid that the pressure acts on and to store energy but in case of incompressible fluid that change is small almost negligible
Bernoullis Equation for flow of gas and changing area Using Bernoulli's equation, I receive a very large negative root or a velocity of about ~550m s in section 1 which seems very ridiculous Is there a better suited equation for this application? The goal is to determine the size of piping needed for section 2
fluid dynamics - What exactly is $h$ in the bernoulli equation . . . The Bernoulli equation, from what I know, relates the pressure to velocity at two different cross-sectional areas of fluid in in the same pipe, with the assumptions of laminar flow, an incompressible fluid, and no viscosity
Bernoullis equation and negative pressure - Physics Stack Exchange In this equation, yes The Bernoulli equation is essentially an energy balance for a fluid at two points And if so, what would that mean? For starters, it means you aren't measuring absolute pressure You could be measuring gauge pressure, or you could have some arbitrary pressure defined as 0
energy - Conflicts between Bernoullis Equation and Momentum . . . The well known Bernoulli's equation states that P + ρV2 2 = c P + ρ V 2 2 = c However, a simple momentum conservation considering P1 P 1 and P2 P 2 acting on two sides, and velocity changes from V1 V 1 to V2 V 2, yields P1 +ρ1V21 =P2 +ρ2V22 P 1 + ρ 1 V 1 2 = P 2 + ρ 2 V 2 2, which differs from Bernoulli's by a coefficient 12 1 2 What is going on here? I understand the derivation of both
Questions about compressible and incompressible Bernoullis equation The Bernoulli's equation is usually thought to be applied to an incompressible fluid (without potential energy change) as 1 2v21 + ρP1 = 1 2v22 + ρP2 1 2 v 1 2 + ρ P 1 = 1 2 v 2 2 + ρ P 2 Where, v is velocity, ρ ρ is the density (which is constant), P is the pressure Q1: Here is there any change in the temperature (internal energy)?
What are the assumptions made to apply the Bernoullis principle in . . . For example, Bernoulli's equation or principle is made as a good equipment in solving real life question regarding lift of aeroplane, blowing out of roofs of houses during storm, vacuum brakes in trains, and many more The problem with me is that why and how we directly apply a theorem for ideal situation to a condition which is non-ideal?