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limits - Can anything equal DNE? - Mathematics Stack Exchange DNE is not necessarily something that doesn't exist It could be the product of D D, N N, and E E Presumably here it stands for the words "does not exist " Do those words not exist? Why would you say that DNE D N E is "something that does not exist?" It's more rational to say the limit is equal to the words Toying with such things is the domain of philosophy In mathematics it's simply a
Which is correct: negative infinity or does not exist? I don't think DNE is unambiguously wrong, as there's no standard definition for what it means In many calculus classes, a limit is said not to exist if there is no real limit, and positive negative infinite limits are a subset of these
Relation between efq, DS, DNE, LEM - Mathematics Stack Exchange DNE LEM DS efq LEM + DS DNE But then, this means that LEM DNE, without any "explicit" need of efq, which refutes a convincing negative stance that DNE requires LEM + efq, leading to obvious confusion Question: I am not at all experienced in logic, and my proofs might be erroneous
Wheel Theory, Extended Reals, Limits, and Nullity: Can DNE limits . . . So this begs another question: is there even any topology on this wheel at all which makes it into a topological wheel and such that real limits are preserved? If so, does such a topology automatically give "DNE" (in the projective reals) limits Φ Φ as a value?
When using the nth term test on a Alternating Series will it always . . . Would that still be DNE? And would mean that the divergence test (nth term test) always passes with the alternating series since it does not equal 0 and always equals DNE DNE times number I saw some other questions on stack exchange similar but they did not answer my specific question about DNE so that is why I am asking
If limit of $f (x)$ exists and the limit of $g (x)$ dne as $x . . . You'll need to complete a few actions and gain 15 reputation points before being able to upvote Upvoting indicates when questions and answers are useful What's reputation and how do I get it? Instead, you can save this post to reference later
If $\\lim_{x \\to a} f(x)$ exist, then $\\lim_{x \\to a} g(x)$ DNE . . . Which should be a contradiction since if f(x) + g(x) corresponds to the limit L + M which exists, by assumption, and then f(x) corresponds to the limit L which also exists, we then have two limits that actually exists, therefore this implies that lim x → ag(x) must also exist Therefore, proving the statement I'd appreciate some advice or any corrections that should be corrected with this