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How do I calculate the molarity of 7. 24 * 10^2 mL of solution . . . = 0 186 ⋅ mol ⋅ L−1 So what's unusual about this problem? It expresses volume in units of mL NOT L But the prefix m stands for milli i e 10−3, just as c stands for centi i e 10−2, and k stands for kilo i e 103, and μ stands for micro i e 10−6 These must be simply be learned, but use them first in practice problems
Question #b6f4c - Socratic Approx 10*mL With all these problems, the priority is to write a stoichiometrically balanced equation: H_2SO_4 (aq) + 2NaOH (aq) rarr Na_2SO_4 (aq) + 2H_2O (l) And thus ONE equiv of sulfuric acid reacts with TWO equiv of sodium hydroxide
If you have a 16 M solution, what volume of water would you . . . - Socratic And so from the initial 16*mol*L^-1 quantity, we takes a volume of (2*mol) (16*mol*L^-1)xx1000*mL*L^-1=0 125*L-=125*mL Note that if you are diluting A CONCENTRATED ACID, the order of addition is ALWAYS ACID TO WATER and NEVER the REVERSE
How to find the dimension formula for inductance and also . . . - Socratic Dimensions of L, MT^(-2)L^2A^(-2) Dimensions of R, ML^2T^(-3)A^(-2) Firstly consider resistance It's defining equation is, Ohm's law, V = IR implies R = V I Now V has units of (electric field)*(distance) But electric field has units (force) (charge) Also, charge has dimensions of (current)(time) and force has dimensions (mass)(length) (time)^2 Thus, dimensions of V is, [V] = (LMLT^(-2
Question #6e3a6 - Socratic Well, to start you need a balanced equation to show molar equivalence I gets approx 0 2*mol*L^-1 with respect to sulfuric acid H_2SO_4 (aq) + 2KOH (aq) rarrK_2SO_4 (aq) + H_2O (l) And thus for each equivalent of sulfuric acid there are TWO equiv potassium hydroxide Given that "concentration"="moles of solute" "volume of solution" "moles of solute"="volume"xx"concentration" And
What is pH of the solution if a. 41*mL of 0. 310*mol*L^-1 . . . - Socratic What is pH of the solution if a 41 ⋅ mL of 0 310 ⋅ mol ⋅ L−1 N aOH (aq) is added to if 31 ⋅ mL of 0 310 ⋅ mol ⋅ L −1 H C l(aq)? And b if a 31 ⋅ mL volume of 0 310 ⋅ mol ⋅ L−1 of H C l(aq) solution are added to 21 ⋅ mL 0 410 ⋅ mol ⋅ L−1 N aOH?