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Lakshmi has a sample of ammonium nitrate (NH - Brainly. com The sample of ammonium nitrate has approximately 0 5010 moles This was calculated by dividing the mass of the sample (40 10 g) by its molar mass (80 0432 g mol) The final answer is reported with the correct number of significant figures
Stoichiometric Calculations Quiz Flashcards | Quizlet Lakshmi has a sample of ammonium nitrate (NH4NO3) that has a mass of 40 10 g She knows that the molar mass of NH4NO3 is 80 0432 g mol To the correct number of significant digits, how many moles of NH4NO3 does the sample contain?
lakshmi has a sample of ammonium nitrate (nh_(4)no_(3)) that has a mass . . . The mass of the sample is given to three significant digits (40 10 g), and the molar mass is given to five significant digits (80 0432 g mol) When performing calculations, the result should be reported with the same number of significant digits as the least precise measurement
[FREE] Lakshmi has a sample of ammonium nitrate (NH4NO3) with a mass of . . . Lakshmi has a sample of ammonium nitrate (NH4NO3) with a mass of 40 10 g The molar mass of NH4NO3 is 80 0432 g mol To the correct number of significant digits, how many moles of NH4NO3 does the sample contain? A 0 50 moles B 0 500979 moles C 0 500980 moles D 0 5010 moles
Lakshmi has a sample of ammonium nitrate (NH4NO3) that has a mass of 40 . . . Determine the formula mass of NH4NO3 by adding the atomic masses of each element in the formula: NH4NO3 = (1 x 14 01) + (4 x 1 01) + (1 x 14 01) + (3 x 16 00) = 80 0432 g mol 2 Use the formula mass to convert the mass of the sample to moles: moles = mass formula mass moles = 40 10 g 80 0432 g mol = 0 5000 mol 3