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Reason for dividing peak value by sq. root 2 to get RMS The peak voltage or current is divided by square root 2 to get the root mean square value please i need a simple derivation just to understand,i will be very greatful for ur consideration thankyou
What is the significance of sqrt {2gh} - Physics Forums Welcome to PF! Hi acspin! Welcome to PF! (have a square-root: √ ) It's because v2 is KE per mass Whenever KE + PE =constant, you'll have equations involving v2 = PE m, which in some cases is gh As to Bernouli's equation, that's just conservation of energy applied to a fluid, and both KE and PE appear in it
Square Root of 4: Can it be +2 or -2? - Physics Forums The square root of 4 can be +2 or -2, your math teacher is retarded What you did with the imaginary number results in what I believe is called an extraneous solution (correct me if I'm wrong) If you substitute the 1 back into your original problem i^2=-1, you will find that 1=-1, which is not a true statement, meaning the solution is incorrect
Significant figures for special functions (square roots) If you use the propagation of errors formula, you will find that taking the square root cuts the relative error in half This buys you 3 dB -- 30% of one significant digit
The square root of a 2x2 matrix - Physics Forums * take the square root (which is now simple because the square root of a diagonal matrix is the diagonal matrix obtained from taking the square root of the diagonal entries), * convert back to the original basis (if desired) The matrix has to be positive semidefinite, so has to have nonnegative eigenvalues
Why does sqrt (24) = 2*sqrt (6)? - Physics Forums (by the definition of square root), and since a,b ≥ 0, √a, √b ≥ 0 (we are only interested in the POSITIVE square root), and positive (to be truly accurate, non-negative) times positive is positive (if one of a,b (or both) is 0, then ab = 0, and the square root of 0 is 0) therefore, (√a) (√b) is indeed the positive square root of ab