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Calculating the odds of a SHA-1 Collision - Grayson Kent Instead of finding matches between people’s birthdays, now you can find matches in 160 bit hashes Diverging from the math we did in first section, we are going to cheat and use an approximation for the finding the amount of files needed for a 50% chance of a match or ‘collision’ in SHA-1
hash - Probability of SHA1 collisions - Stack Overflow That's Birthday Problem - the article provides nice approximations that make it quite easy to estimate the probability Actual probability will be very very very low - see this question for an example
Probability of GitHub Repository Identifier SHA1 Hash Collisions SHA-1 produces a 160-bit hash value, which means there are 2^160 (approximately 1 46 x 10^48) possible hash values To calculate the probability of a collision, we can use the birthday problem approximation, which is appropriate when the number of items (n) is much smaller than the square root of the number of possible hash values (H)
SHA-1 Collisions - TLSeminar SHA-1 takes an arbitrary length message and computes a 160-bit hash It divides the (padded) input into k k blocks M1,M2, …,Mk M 1, M 2, …, M k of 512 bits
How hard is it to get a Git hash collision? - Diego Assencio Every time a commit is added to a Git repository, a hash string that identifies this commit is generated This hash is computed with the SHA-1 algorithm and is 160 bits (20 bytes) long Expressed in hexadecimal notation, such hashes are 40-digit strings
math - Probability of hash collision - Stack Overflow I am looking for some precise math on the likelihood of collisions for MD5, SHA1, and SHA256 based on the birthday paradox I am looking for something like a graph that says "If you have 10^8