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verilog - What does always block @ (*) means? - Stack Overflow The (*) means "build the sensitivity list for me" For example, if you had a statement a = b + c; then you'd want a to change every time either b or c changes In other words, a is "sensitive" to b c So to set this up: always @( b or c ) begin a = b + c; end But imagine you had a large always block that was sensitive to loads of signals Writing the sensitivity list would take ages In fact
Verilog Always block using (*) symbol - Stack Overflow The always @(*) syntax was added to the IEEE Verilog Std in 2001 All modern Verilog tools (simulators, synthesis, etc ) support this syntax Here is a quote from the LRM (1800-2009): An incomplete event_expression list of an event control is a common source of bugs in register transfer level (RTL) simulations The implicit event_expression, @*, is a convenient shorthand that eliminates these
Docker - what does `docker run --restart always` actually do? docker run --always Always restart the container regardless of the exit status When you specify always, the Docker daemon will try to restart the container indefinitely The container will also always start on daemon startup, regardless of the current state of the container I recommend you this documentation about restart-policies
Always vs forever in Verilog HDL - Stack Overflow The always construct can be used at the module level to create a procedural block that is always triggered Typically it is followed by an event control, e g , you might write, within a module, something like: always @(posedge clk) <do stuff> always @(en or d) <do stuff> always @* <do stuff>, can also use @(*) This is the typical way to write latches, flops, etc The forever construct, in
verilog - Use of forever and always statements - Stack Overflow The difference between forever and always is that always can exist as a "module item", which is the name that the Verilog spec gives to constructs that may be written directly within a module, not contained within some other construct initial is also a module item always blocks are repeated, whereas initial blocks are run once at the start of
Does the C# finally block ALWAYS execute? [duplicate] No it does not It will always execute provided the application is still running (except during a FastFail exception, MSDN link, like others noted) It will execute when it exits the try catch portion of the block It will NOT execute if the application crashes: gets killed through a kill process command etc This is highly important, because if you write code that absolutely expects it to run
Change Always On setting for Azure Function App I've an Azure Function App - created with the setting "Always On" and a matching AppServicePlan behind Now, I want to change the setting of "Always On" to false off but I couldn't find the setting neither in Settings->Configuration nor in other tabs like Settings-->Properties