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How can I determine a Python variables type? - Stack Overflow In Python code, this shouldn't make a bit of difference because the interpreter automatically converts to long when a number is too large If you want to know about the actual data types used in the underlying interpreter, that's implementation dependent
python - Immutable vs Mutable types - Stack Overflow All variables can be reassigned in Python, whether they were previously assigned to mutable or immutable types However, the behavior of reassignment is different for mutable and immutable types, and cannot be thought of purely in traditional C and C++-like memory terms and understanding
How to declare variable type, C style in Python - Stack Overflow In Python, objects exist out there in the interpreter's memory jungle, and you can give them names and remember where to find them using variables Your variable doesn't have a type in the C sense, it just points to an object
How to force ensure class attributes are a specific type? In Python, primitive data types (int, float, str, booleans) are themselves classes Thus if you instantiate the class attributes of your class before passing the method parameters during object creation, the argument values will be converted if possible (such as from a int to a float) or an exception will be thrown if the data type cannot be
strong typing - Is Python strongly typed? - Stack Overflow Python is strongly, dynamically typed Strong typing means that the type of a value doesn't change in unexpected ways A string containing only digits doesn't magically become a number, as may happen in Perl Every change of type requires an explicit conversion Dynamic typing means that runtime objects (values) have a type, as opposed to static typing where variables have a type As for your
python - Viewing all defined variables - Stack Overflow You do get a list of the variables, which answers the question, but with incorrect types listed beside them This was not obvious in your example because all the variables happened to be strings anyway; however, what it's returning is the type of the name of the variable instead of the type of the variable