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ABT ACCESSORIES WAREHOUSE

HALIFAX-Canada

Company Name:
Corporate Name:
ABT ACCESSORIES WAREHOUSE
Company Title:  
Company Description:  
Keywords to Search:  
Company Address: 10 Ragged Lake Blvd,HALIFAX,NS,Canada 
ZIP Code:
Postal Code:
B3S 
Telephone Number: 9024501940 
Fax Number:  
Website:
 
Email:
 
USA SIC Code(Standard Industrial Classification Code):
0 
USA SIC Description:
Coffee & Tea 
Number of Employees:
1 to 4 
Sales Amount:
Less than $500,000 
Credit History:
Credit Report:
Unknown 
Contact Person:
 
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  • How to prove $(AB)^T=B^T A^T$ - Mathematics Stack Exchange
    Given an m × n m × n -matrix A A and an n × p n × p -matrix B B Prove that (AB)T = BTAT (A B) T = B T A T Here is my attempt: Write the matrices A A and B B as A = [aij] A = [a i j] and B = [bij] B = [b i j], meaning that their (i, j) (i, j) -th entries are aij a i j and bij b i j, respectively Let C = AB = [cij] C = A B = [c i j], where cij =∑n k=1aikbkj c i j = ∑ k = 1 n a i k b k
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  • A confusion in the proof of $(AB)^T = (B^T A^T)$
    You seem to know that (i, j) (i, j) -entry of BT B T is bj,i b j, i, that is probably why you are writing BT = (bj,i) B T = (b j, i) The issue is, this notation is confusing as it is not telling you which index denotes the row and which denotes the column I guess this is where you get confused To make things clear, let us use some unconventional notation: A matrix A A whose (i, j) (i, j




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