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I understanding the formula Power loss= I^2 R - Physics Forums The practical explanation for I^2R, is that the power ( measured in Watts) is equal to the single variable of current "I", (which becomes squared in this equation, as you have confirmed mathematically) times the resistance (R) along that path of a circuit So as long as you keep the resistance small, you can minimize the power consumed or lost as heat
When to use P=I^2R, P=VI, P=V^2 R? - Physics Forums Hi, I know that P = I^2R is to find heat loss but can we use P = V^2 R or P = IV to find the heat loss? simply when do we use which?? (or can we use all anytime?)
Understanding Power in Parallel Circuits: V^2 R vs. i^2R P= Vi , P= V^2 R , P= i^2R [ B] The Attempt at a Solution Physics news on Phys org Measuring individual radioactive decays enables faster detection method for nuclear applications Spin as an input parameter: Machine learning predicts magnetic properties of materials Quantum clocks deliver navigation accuracy far beyond current GPS systems in
Why is power loss = I^2R instead of P=VI or P=I^2R? - Physics Forums My textbook states that power loss = I^2R, but why? Could someone explain please? thank you Last edited by a moderator: Oct 26, 2016 Physics news on Phys org 2014 Nobel Prize idea used to reach super-resolution imaging, turning noise into data Where did all the antimatter go? This mismatch in how subatomic particles behave could hold a clue
Can the Separable First Order ODE be solved with a different answer? Don't forget brackets in writing, it may confuse people We have ∫ -2r (r⁴+1) dr = ∫ 1 (s²+1) ds The left integral gives -arctan (r²), the right arctan (s), so c - arctan (r²) = arctan (s) (You forgot the minus sign from the variable change) Taking the tangens on both sides and using the addition theorem we have s = tan [ c - arctan (r²) ] = ( tan c - r² ) ( 1 + r² tan c
Net Torque Rotational Dynamics Pulley System help Homework Equations \sumF=ma \sum\tau = I\alpha I = md 2 The Attempt at a Solution Let's take downward to be positive For the block: \sumF=ma mg - T 1 = ma For the cylinder: Rotational: \sum\tau = I\alpha T 2 2R = 1 2m (2R) 2 \alpha Translational: T 2 - f = ma For the Pulley: T 1 R-T 2 R = I\alpha Okay so I am fairly new to understanding torque First I want to know if my equations are correct
Two equations for centripetal acceleration - Physics Forums My question is how can Ac (centripetal acceleration) be both inversely related to radius and directly related in two equations: 1) Ac = V2 r 2) Ac = 4pi2r T2 In the first equation Ac is inversely proportional to radius in the second one Ac is directly proportional to radius Why and how is
With a circular orbit, when do I use 1 2mv^2 - Physics Forums The Attempt at a Solution For instance, when I tried to use the other kinetic energy equation (GMm 2r) to solve the kinetic energy of a satellite at perigee, it gave a totally different answer if I use 1 2mv^2 Physics news on Phys org 2014 Nobel Prize idea used to reach super-resolution imaging, turning noise into data Where did all the