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- A circular disc of radius R is removed from a bigger circular d
A circular disc of radius R is removed from a bigger circular disc of radius 2R such that the circumferences of the discs coincide The center of mass of new disc is αR from the center of the bigger disc
- A circular disc of radius R is removed from a bigger circular disc of . . .
We are using the concept that, if we put the cutout section, and remaining disc at the original position, it will give back the original disc So, the effective centre of mass will be at the origin
- A circular portion of radius r is removed from a uniform . . . - Filo
To find the shift in the center of mass when a circular portion of radius 'r' is removed from a larger disc of radius '4r', we can use the concept of center of mass for composite bodies
- From a uniform circular disc of radius R and mass 9 M,
From a uniform circular disc of radius R and mass 9 M, a small disc of radius R 3 is removed as shown in the figure The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through centre of disc is :
- Cavity Problems - Concepts of Physics
Problem (JEE Mains 2007): A circular disc of radius $r$ is removed from a bigger circular disc of radius $2r$ such that the circumferences of the discs coincide
- A circular disc of radius R is removed from a bigger circular disc of . . .
A circular disc of radius R is removed from a bigger circular disc of radius 2R, such that the circumferences of the discs coincide The centre of mass of the new disc is α R from the centre of the bigger disc
- From a circular disc of radius R, another disc of diameter R is remove
The height of the cone is 10 Cm and the radius of the base is 7 cm Determine the volume of the toy Also find the area of the coloured sheet required to cover the toy
- From a circular disc of radius R and mass 9M, a small disc of mass M . . .
Now, moment of inertia of disc rotating along the axis passing through its centre and perpendicular to the plane, can be given by the formula, ⇒ I = 40 9 M R 2 Hence, option (a) is the correct answer
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