|
- Docker Desktop - An unexpected error was encountered while executing a . . .
Run the following commands in PowerShell to ensure WSL is up to date and restart it: wsl --update wsl --shutdown Additionally, check your BIOS settings: • If you have an AMD CPU, ensure SVM (Secure Virtual Machine) is enabled • If you have an Intel CPU, make sure VT-x (Virtualization Technology for x86) is enabled
- How to change the order of DataFrame columns? - Stack Overflow
For a generalized NumPy-based solution see How to move a column in a pandas dataframe, assumes one column level only, i e no MultiIndex
- python - How do I sort a dictionary by key? - Stack Overflow
How do I sort a dictionary by its keys? Example input: {2:3, 1:89, 4:5, 3:0} Desired output: {1:89, 2:3, 3:0, 4:5}
- Performance optimization strategies of last resort
Performance optimization strategies of last resort [closed] Asked 16 years, 1 month ago Modified 7 months ago Viewed 95k times
- It will always be more efficient to use more specific change events if . . .
It will always be more efficient to use more specific change events if you can Rely on notifyDataSetChanged as a last resort RecycleView edit question: the want us to use DiffUtil docs instead of notifyDataSetChanged () because it much faster check this article on medium
- Difference between scikit-learn and sklearn (now deprecated)
Regarding the difference sklearn vs scikit-learn: The package "scikit-learn" is recommended to be installed using pip install scikit-learn but in your code imported using import sklearn A bit confusing, because you can also do pip install sklearn and will end up with the same scikit-learn package installed, because there is a "dummy" pypi package sklearn which will install scikit-learn for
- sql - Resort (reorder) table data - Stack Overflow
What is the fastest way to reorder (resort) a table so that the physical representation most closely matches the logical, using PostgreSQL?
- Display the resortid, name of the resort ,booking count and the total . . .
count(*) totalbooking , sum(b totalcharge) as totalamount from resort r inner join booking b on b resortid = r resortid group by r resortid, r resortname order by r resortid; Note that table aliases make the query easier to write and read This gives you one row per resort, with the total number of bookings and the sum of totalcharge
|
|
|