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- Calculating Kinetic Energy for an Object at an Angle - Physics Forums
I have a question regarding how to calculate kinetic energy Let's say I was to find the kinetic energy of a ball shot at 180 m s at a 45 degree angle Do i simply sub in 180 as v (velocity) in the kinetic energy equation (1 2mv^2) or must it be split into components?
- Calculating Kinetic Energy in English Units - Physics Forums
Homework Statement An object has a mass of 10 lbm b Find the change in kinetic energy ft·lbf when its velocity decreases from 50 mph to 15 mph Homework Equations KE=1 2mv^2 Ke=(ft*lbf) 1MPH=1 4667 ft s The Attempt at a Solution When calculating this, does it need to be in slugs, lbm, or
- Can anybody explain the formula for Kinetic Energy? - Physics Forums
But the kinetic energy is $\int \vec{p} \bullet d \vec{v} = m \int \frac{d \vec{x}}{dt} \bullet dfrac{d \vec{x}}{dt}$ It seems as though this is saying that the first derivative squared is equal to the second derivative of x with respect to t The same thing happens in the Schrodinger equation, when p is squared to set up the kinetic energy
- Is Negative Kinetic Energy Real in Quantum Systems? - Physics Forums
i see, thanks for replying but i didnt invent tachyon theory, and one of reports from mathematical construction model of tachyon cleary stated that e=mc2 statement and if something has a mass and velocity it has kinetic energy in non-relativistic energy ranges we could apply e=(mv2) 2 but I am sure that more quantum laws interfere in that
- Kinetic energy of a rotating disc - Physics Forums
Then the rotational kinetic energy around that axis simplifies to 1 2 Iω², which starts to resemble the normal kinetic energy equation you are used to For a solid disk, there is a simple expression for moment of inertia around rotational symmetry axis, which is typically the axis you think of disk rotating through
- Flow work and kinetic energy in fluid flow - Physics Forums
"Flow energy" is basically work done by pressure forces on a fluid element and this work must result in a change in kinetic energy of the element What I mean to say is that change in kinetic energy of the fluid element is the result of work done by pressure forces Thus, flow work is expended to increase kinetic energy of the fluid as the work
- Amount of energy, roughly, needed to kill with blunt force trauma
Basically, I have been trying to solve my own fictional equation of the amount of weight mass needed to be dangerous or lethal from roughly 400 feet in the air I have tried multiple equations and what not to come to no answer besides the answer to the amount of kinetic energy
- Calculating Percent of Kinetic Energy Lost - Physics Forums
Then I used the Velocities after the collision, plugged them into the kinetic energy equation and added those 2 up Now that I have the Ke initial and Ke final I subtracted them and found out how much was lost Taking the amount lost over the intial amount of kinetic energy Getting what I assume is the % of kinetic energy lost
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