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- Question #c548d - Socratic
Question 1: K_ (sp)= 1 1 xx10^ (-11) Question 2: s= 4 9 xx10^ (-12)M Quest (1) determine the ksp for magnesium hydroxide Mg (OH)_2 where the molar solubility of Mg
- Question #9f499 - Socratic
Explanation: Your starting point here is the pH of the solution More specifically, you need to use the given pH to determine the concentration of hydroxide anions, #"OH"^ (-)#, present in the saturated solution
- Question #e7848 - Socratic
Similarly, OH^- becomes H_2O, indicating a gain of a H^+ ion So, you can say that NH_4^+ is the acid, and OH^- is the base Conjugates are basically the "other" term For every acid, you have a conjugate base (that no longer has that extra H^+ ion), and for every base, you have a conjugate acid (that has an extra H^+ ion)
- Can you give the IUPAC name for the following (CH_3)_3C-OH . . . - Socratic
So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2-ol" I think this is right, and I haven't broken any arcane rule Both names seem to be unambiguous
- Question #d6b18 - Socratic
We want the standard enthalpy of formation for Ca (OH)_2 Thus, our required equation is the equation where all the constituent elements combine to form the compound, i e : Ca +H_2+O_2->Ca (OH)_2 Let us now write down the given equations: [The first equation mentioned is incorrect, and so I have revised it ] (1) 2H_2 (g) + O_2 (g)->2H_2O (l) and DeltaH_1=-571 66 kJmol^-1 (2) CaO (s) + H_2O (l
- Question #18488 - Socratic
The degree of dissociation sf (alpha=0 0158) sf (K_b=2 51xx10^ (-6)color (white) (x)"mol l") Triethyamine is a weak base and ionises: sf ( (CH_3)_3N+H_2Orightleftharpoons (CH_3)_3stackrel (+) (N)H+OH^-) For which: sf (K_b= ( [ (CH_3)_3stackrel (+) (N)H] [OH^ (-)]) ( [ (CH_3)_3N])) Rearranging and taking -ve logs of both sides we get the
- How many grams of \text {NH}_4\text {OH} do I need to make . . . - Socratic
"6 3072 g" >>"Molarity" = "Moles of solute" "Volume of solution (in litres)" "0 45 M" = "n" "0 4 L" "n = 0 45 M × 0 4 L = 0 18 mol" You need "0 18 mol" of "NH"_4"OH" Molar mass of "NH"_4"OH" is "35 04 g mol" Mass of solute = 0 18 cancel"mol" × "35 04 g" cancel"mol" = "6 3072 g"
- What is the product of the following reaction? 1)CH_3 OH - Socratic
These are ostensibly acid-base reactions For ammonium we could write NH_4^+ +HO^(-) rarr NH_3(aq) + H_2O(l) For methanol, the acid base reaction would proceed
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