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- kubernetes - kubectl logs - continuously - Stack Overflow
kubectl logs lt;pod-id gt; gets latest logs from my deployment - I am working on a bug and interested to know the logs at runtime - How can I get continuous stream of logs ? edit: corrected quest
- How to find nPr (permutations) efficiently? - Stack Overflow
4 How about this: nPr = (n−1)Pr + (n−1)P (r−1) ⋅ r Rationale: nPr denotes the number of ways to choose r elements from n while noting their order and not putting them back In the above recursion I distinguish two cases Either you don't choose the n th element, in which case you'll be choosing all your r elements from a set of (n−1)
- counting combinations and permutations efficiently
I have some code to count permutations and combinations, and I'm trying to make it work better for large numbers I've found a better algorithm for permutations that avoids large intermediate resu
- What are all of the Maven Command Line Options? - Stack Overflow
I'm looking for the list of options for Maven 2 2 but cannot find it If someone knows the location please post it Thank you I found the following but I don't know enough of Maven to know which a
- dumping vcd files in Modelsim simulations - Stack Overflow
You need to add a runtime optimization switch -voptargs=+acc=npr to preserve signal visibility I'll put in a request to have this on by default
- NPR ran a prepper episode last Friday. . . | Survivalist Forum
Chased down a link for you all Can you really 'prep' for the breakdown of society? For anywhere from $100 to $3,000 or more, you can get ready for doomsday with a prepper kit Michael Mills, lecturer in criminology at the University of Kent, joins host Krys Boyd to discuss the phenomenon of
- Best program for Permutation nPr of large numbers
I am new to programming and was stuck at the permutation part I have code which works for combination of large numbers which is stored in matrix but i am not able to find what should i change in t
- VIN Validation RegEx - Stack Overflow
4 [A-HJ-NPR-Za-hj-npr-z\d]{2} This allows for 2 characters, composed of any digits and any letters except I, O, and Q; it properly finds the next 2 characters: bf \d{6}$ This allows for exactly 6 digits, and is the reason the regex fails; because the final 6 characters are not all digits: c45903
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