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- OR condition in Regex - Stack Overflow
For example, ab|de would match either side of the expression However, for something like your case you might want to use the ? quantifier, which will match the previous expression exactly 0 or 1 times (1 times preferred; i e it's a "greedy" match) Another (probably more relyable) alternative would be using a custom character group:
- regex - Matching strings in PowerShell - Stack Overflow
I'm trying to match the file names against the recorded names in my CSV file It generally works, but sometimes I get incorrect matches Let's say I have two files that start similarly, Apple and Apple_Pie Apple will match to Apple and move to the right directory, but Apple_Pie will first match to Apple and move to the wrong directory
- Regular expression to stop at first match - Stack Overflow
you can match a[^ab]*b i e specify a character class which excludes the starting and ending delimiiters In the more general case, you can painstakingly construct an expression like start(|[^e]|e(|[^n]|n(|[^d])))*end to capture a match between start and the first occurrence of end
- Regex: ignore case sensitivity - Stack Overflow
G[a-b] * i string match("G[a-b] *", "i") Check the documentation for your language platform tool to find how the matching modes are specified If you want only part of the regex to be case insensitive (as my original answer presumed), then you have two options:
- How do if statements differ from match case statments in Python?
This question asks for a switch case or match case equivalent in Python It seems since Python 3 10 we can now use match case statement I cannot see and understand the difference between match case and an if, elif statement other than the syntactical differences!
- How can I compare two lists in python and return matches
A quick performance test showing Lutz's solution is the best: import time def speed_test(func): def wrapper(*args, **kwargs): t1 = time time() for x in xrange(5000): results = func(*args, **kwargs) t2 = time time() print '%s took %0 3f ms' % (func func_name, (t2-t1)*1000 0) return results return wrapper @speed_test def compare_bitwise(x, y): set_x = frozenset(x) set_y = frozenset(y) return set
- Regex - how to tell something NOT to match? - Stack Overflow
OK, but of course then the match result will be an empty string (with a successful match) If you're just checking whether a match is possible, then this doesn't matter So yes, omit the *$, and you're done faster –
- Excel VLOOKUP - not detecting matches - Stack Overflow
There are some cases where the formula returns "#N A", as if the match cannot be found in the lookup list, but where in fact there is a match in the list e g 300431419 (row 27 in the main data sheet) I've checked for extra spaces or anything else that would prohibit a match but cannot see anything
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