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- logarithms - What is the best way to calculate log without a calculator . . .
As the title states, I need to be able to calculate logs (base $10$) on paper without a calculator For example, how would I calculate $\\log(25)$?
- Natural log of a negative number - Mathematics Stack Exchange
My teacher told me that the natural logarithm of a negative number does not exist, but $$\ln (-1)=\ln (e^ {i\pi})=i\pi$$ So, is it logical to have the natural logarithm of a negative number?
- logarithms - Log of a negative number - Mathematics Stack Exchange
For example, the following "proof" can be obtained if you're sloppy: \begin {align} e^ {\pi i} = -1 \implies (e^ {\pi i})^2 = (-1)^2 \text { (square both sides)}\\ \implies e^ {2\pi i} = 1 \text { (calculate the squares)}\\ \implies \log (e^ {2\pi i}) = \log (1) \text { (take the logarithm)}\\ \implies 2\pi i = 0 \text
- logarithms - Interpretation of log differences - Mathematics Stack Exchange
I have a very simple question I am confused about the interpretation of log differences Here a simple example: $$\\log(2)-\\log(1)= 3010$$ With my present understanding, I would interpret the resul
- What is the point of logarithms? How are they used? [closed]
Logarithms are defined as the solutions to exponential equations and so are practically useful in any situation where one needs to solve such equations (such as finding how long it will take for a population to double or for a bank balance to reach a given value with compound interest) Historically, they were also useful because of the fact that the logarithm of a product is the sum of the
- logarithms - Dividing logs with same base - Mathematics Stack Exchange
Dividing logs which have the same base changes the base of the log That is log a log b =logb a log a log b = log b a It doesn't matter what base we were using on the left hand side It will change the base of the log as above log 125 log 25 =log25 125 log 125 log 25 = log 25 125 and 253 2 = 125 25 3 2 = 125
- Multiplying two logarithms (Solved) - Mathematics Stack Exchange
I was wondering how one would multiply two logarithms together? Say, for example, that I had: $$\\log x·\\log 2x lt; 0$$ How would one solve this? And if it weren't possible, what would its doma
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