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- When do we use common logarithms and when do we use natural logarithms
Currently, in my math class, we are learning about logarithms I understand that the common logarithm has a base of 10 and the natural has a base of e But, when do we use them? For example the equ
- Easy way to compute logarithms without a calculator?
I would need to be able to compute logarithms without using a calculator, just on paper The result should be a fraction so it is the most accurate For example I have seen this in math class calc
- What algorithm is used by computers to calculate logarithms?
The GNU C library, for example, uses a call to the fyl2x() assembler instruction, which means that logarithms are calculated directly from the hardware So the question is: what algorithm is used by computers to calculate logarithms?
- Multiplying two logarithms (Solved) - Mathematics Stack Exchange
I was wondering how one would multiply two logarithms together? Say, for example, that I had: $$\\log x·\\log 2x lt; 0$$ How would one solve this? And if it weren't possible, what would its doma
- Logarithms with negative bases for real numbers
It is in that scenario that I have always only understood logarithms as defined for positive numbers, although there seems to be solutions for negative bases My apologies if that wasn't clear
- How to multiply two different logarithms.
How to calculate expression like this one below? $\\log_7(19) \\log_2(5) = \\log_x(y)$ Or at least where can I find any information about expressions like this Examples and explanation that I found in
- Why roots arent the inverse of exponentiation but logarithms?
Why roots aren't the inverse of exponentiation but logarithms? Ask Question Asked 1 year, 9 months ago Modified 1 year, 9 months ago
- logarithms - Log of a negative number - Mathematics Stack Exchange
For example, the following "proof" can be obtained if you're sloppy: \begin {align} e^ {\pi i} = -1 \implies (e^ {\pi i})^2 = (-1)^2 \text { (square both sides)}\\ \implies e^ {2\pi i} = 1 \text { (calculate the squares)}\\ \implies \log (e^ {2\pi i}) = \log (1) \text { (take the logarithm)}\\ \implies 2\pi i = 0 \text
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