- complex analysis - How to derive the value of $\log (-1 . . .
How to derive the value of $\log (-1)$? Ask Question Asked 10 years, 3 months ago Modified 10 years, 3 months ago
- How to figure out the log of a number without a calculator?
The first link is simply using the basic rules for logarithms - the log of a product is equal to the sum of the logs (working in base 10)
- verbs - log in to or log into or login to - English Language . . .
The difference between "log in to host com" and "log into host com" is entirely lexical, so it really only matters if you're diagramming the sentence Personally, I prefer to avoid prepositional phrases when possible, so I would write, "log into host com "
- Logged-in, log-ined, login-ed, logined, log-in-ed, logged in?
49 Log in is a verb, while login is a noun Its Past Tense is logged in (I logged in yesterday) As an attributive phrase, it is logged-in (logged-in users)
- Why there is no formula $\\log(a) *\\log(b) = $(something)?
The formula is not particularly useful, but it is log a ⋅ log b = logblog a = logalog b log a log b = log b log a = log a log b If you like, you can rewrite the division formula as log b ⋅logb a = log a log b log b a = log a, which would be significantly more useful
- logarithms - log base 1 of 1 - Mathematics Stack Exchange
5 If we defined log1 1 log 1 1, we would want it to satisfy the basic properties that log satisfies One of these properties is aloga b = b a log a b = b Well, this is bad, because setting a = 1 a = 1, we find that 1log1 b =1stuff = 1 1 1 b = 1 = 1, so the equation works only when b = 1 b = 1 But suppose we ignore this property
- algebra precalculus - How is $2^ {\log_4 n}= n^ {\log _42 . . .
BTW, if we take $\log_2$ of both sides we get: $$ {\log_4 n} = {\log _42}\log_2 n= \frac 1 2 \log_2 n$$ which makes both sides look even more different
- Easy way to remember Taylor Series for log (1+x)?
I think something is wrong with the derivation you have - notably, the first equation, $\log (1-x)=-\sum_ {n=1}^ {\infty}x^n$ is not true - you probably want a log around the sum on the left
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