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- python - How to convert list to string - Stack Overflow
Agree with @Bogdan This answer creates a string in which the list elements are joined together with no whitespace or comma in between You can use ', ' join(list1) to join the elements of the list with comma and whitespace or ' ' join(to) to join with only white space –
- python - if else in a list comprehension - Stack Overflow
Since a list comprehension creates a list, it shouldn't be used if creating a list is not the goal; it shouldn't be used simply to write a one-line for-loop; so refrain from writing [print(x) for x in range(5)] for example
- What is the syntax to insert one list into another list in python?
List slicing is quite flexible as it allows to replace a range of entries in a list with a range of
- slice - How slicing in Python works - Stack Overflow
The first way works for a list or a string; the second way only works for a list, because slice assignment isn't allowed for strings Other than that I think the only difference is speed: it looks like it's a little faster the first way Try it yourself with timeit timeit() or preferably timeit repeat()
- Command to list all files in a folder as well as sub-folders in windows
To print specific file present in the folders sub-folders for eg : If you want to list just the csv files then : dir b s A-D o:gn * csv >list txt If you want to also include xlsx files then the code is : dir b s A-D o:gn * csv * xlsx >list txt You can mention more file types in the same way P S Got to know this one from chatgpt :P
- Get a list from Pandas DataFrame column headers
Create a list of keys columns - object method to_list() and the Pythonic way: my_dataframe keys() to_list() list(my_dataframe keys()) Basic iteration on a DataFrame returns column labels: [column for column in my_dataframe] Do not convert a DataFrame into a list, just to get the column labels
- Array versus List lt;T gt;: When to use which? - Stack Overflow
Using e g List<Point> list, it would be necessary to instead say Point temp=list[3]; temp x+=q; list[3]=temp; It would be helpful if List<T> had a method Update<TP>(int index, ActionByRefRef<T,TP> proc, ref TP params) and compilers could turn list[3] x+=q; into {list Update(3, (ref int value, ref int param)=>value+=param, ref q); but no
- How do I subtract one list from another? - Stack Overflow
However, this still has a problem from quantumSoup's version: It requires your elements to be hashable That's pretty much built into the nature of sets ** If you're trying to, e g , subtract a list of dicts from another list of dicts, but the list to subtract is large, what do you do?
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