- What does the exclamation mark do before the function?
function foo() {} Note that there’s no semicolon; this is just a function declaration You would need an invocation, foo(), to actually run the function Now, when we add the seemingly innocuous exclamation mark: !function foo() {} it turns it into an expression It is now a function expression
- How do function pointers in C work? - Stack Overflow
357 Function pointers in C can be used to perform object-oriented programming in C For example, the following lines is written in C:
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