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- algebra precalculus - Evaluating $\frac {1} {a^ {2025}}+\frac {1} {b . . .
When I tried to solve this problem, I found a solution (official) video on YouTube That is a = −b, c = 2024 a = b, c = 2024 and the correct answer is 1 20242025 1 2024 2025 Is there an alternative solution but not using (a + b)(a + c)(b + c) + abc = (a + b + c)(ab + ac + bc) (a + b) (a + c) (b + c) + a b c = (a + b + c) (a b + a c + b c) ?
- Evaluating $\\sqrt{119^2+120^2}$ with clever algebra
Numbers $(119,120,169)$ are Pythagorean triples, i e $119^2+120^2=169^2$ I'm wondering is it possible to start from $119^2+120^2$ and get $169^2$ algebraically without evaluating $119^2$ and $120
- Evaluating $ \\lim_{x \\to 0} \\frac{e - (1 + 2x)^{1 2x}}{x} $ without . . .
Evaluating limx→0 e−(1+2x)1 2x x lim x → 0 e (1 + 2 x) 1 2 x x without using any expansion series [closed] Ask Question Asked 10 months ago Modified 10 months ago
- complex numbers - Evaluating $2^i$ - Mathematics Stack Exchange
It is obvious that we should use Euler's formula, but the fact that $\\Vert e^{i \\alpha} \\Vert = 1$ (while the base is 2) brings difficulty of using it Can anyone think of a way evaluate this Tha
- calculus - Evaluating $\int \frac {x^3} {\sqrt {x^2 + 4x + 6}} dx . . .
Evaluating ∫ x3 x2+4x+6√ dx ∫ x 3 x 2 + 4 x + 6 d x Ask Question Asked 2 years, 6 months ago Modified 8 months ago
- integration - Evaluating $\int_ {0}^ {2\pi}\cos ^2 (x)\sin (x) \ dx . . .
Evaluating ∫2π 0 cos2(x) sin(x) dx ∫ 0 2 π cos 2 (x) sin (x) d x Ask Question Asked 1 year, 1 month ago Modified 1 year, 1 month ago
- Evaluating $\\lim\\limits_{x\\to-3}\\frac{x^2-9}{2x^2+7x+3}$
The important thing to know at this level of evaluating limits is that if the numerator is zero, you can only conclude the whole thing is zero if the denominator is not zero We sometimes say 0 0 0 0 is indeterminate, because depending on how one gets to this symbolic expression 0 0 0 0, the actual limit may be any real number (or even±∞ ±
- Evaluating $\\lim\\limits_{n\\to\\infty} e^{-n} \\sum\\limits_{k=0}^{n . . .
I'm supposed to calculate: $$\\lim_{n\\to\\infty} e^{-n} \\sum_{k=0}^{n} \\frac{n^k}{k!}$$ By using WolframAlpha, I might guess that the limit is $\\frac{1}{2
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