Why is the exponential integral $\operatorname {Ei} (x)$ the . . . $$\operatorname {Ei} (x)=\operatorname {Ei} (-1)-\int_ {-x}^1\frac {e^ {-t}}t~\mathrm dt$$ which are both easily differentiated using the fundamental theorem of calculus, now that we have finite bounds, and the chain rule to get $$\operatorname {Ei}' (x)=\frac {e^x}x$$ Note that where you choose to split the integral is arbitrary
Quiz: Spelling- ie and ei - UsingEnglish. com Quiz: Spelling- 'ie' and 'ei' This is a intermediate-level quiz containing 10 multichoice quiz questions from our 'spelling and punctuation' category Simply answer all questions and press the 'Grade Me' button to see your score This exercise is also available as a printable worksheet
Evaluate $\\int \\frac{e^x [\\operatorname{Ei}(x) \\sin(\\ln x . . . So I tried some u-sub like Ei(x) lnx Ei (x) ln x, li(x) lnx li (x) ln x but I think it's some other u-substitute (I tried to show effort but everything stops here) (I create this before but I forgot the trick)
integration - Closed form of $\operatorname {Ei} (-t) \theta (t) \star . . . You'll need to complete a few actions and gain 15 reputation points before being able to upvote Upvoting indicates when questions and answers are useful What's reputation and how do I get it? Instead, you can save this post to reference later