electrostatics - Trick question: why do dielectrics and isolated . . . Trick question: Dielectric material produces net surface charge when placed in electric field Isolated conductor also produces net surface charge when placed in electric field However, dielectric increases capacitance when placed in-between plates of capacitor while isolated conductor seems to decreases capacitance Why is that?
electrostatics - Why is capacitance increased with a dielectric rather . . . A dielectric with high permittivity $\varepsilon$ permits (requires) more polarization for a given field magnitude than a low permittivity one More polarization means more charge stored, so the high $\varepsilon$ material must hold more charge for a given field to be measured across it when used as a dielectric in a capacitor
Displacement current in a dielectric - Physics Stack Exchange Further, this would imply that the equation for net displacement current in a dielectric medium would be $\epsilon_ok \frac {d\phi_E} {dt}$ However, this result doesn't make intuitive sense to me Could someone please explain if there's a problem with my thinking here?
Conductor-Dielectric Boundary Conditions - Physics Stack Exchange 2 We have a conductor of resistivity $\rho$ and has a boundary with a dielectric of permittivity $\epsilon$ and we have displacement vector $\vec D$ at an angle $\alpha$ with normal to the boundary and directed from conductor to the dielectric I need to find the conductor's surface charge density and current density in the vicinity of the
Surface charge on dielectric interface - Physics Stack Exchange As the dielectric constant of the plates are different, I would expect a surface density at the interface of the two dielectric materials I want to calculate this surface charge density I have the following figure in my mind but with two different slabs of dielectrics (area and length are the same)