- limits - Can anything equal DNE? - Mathematics Stack Exchange
Considering this, it would make more linguistically and notationally valid sense to replace ‘ $=\mathtt{DNE}$ ’ with ‘ $\:\mathtt{DNE}$ ’ (omitting, or for typographic clarity instead substituting with a space or two, the ‘ $=$ ’)
- Relation between efq, DS, DNE, LEM - Mathematics Stack Exchange
DNE $\implies$ LEM $\implies$ DS $\iff$ efq; LEM + DS $\implies$ DNE; But then, this means that LEM $\iff$ DNE, without any "explicit" need of efq, which refutes a convincing negative stance that DNE requires LEM + efq, leading to obvious confusion Question: I am not at all experienced in logic, and my proofs might be erroneous Thus, if
- Which is correct: negative infinity or does not exist?
$\begingroup$ I don't think DNE is unambiguously wrong, as there's no standard definition for what it means In many calculus classes, a limit is said not to exist if there is no real limit, and positive negative infinite limits are a subset of these $\endgroup$
- Multivariable Calculus question, show limit of equation DNE
$\begingroup$ The question asks to show that the limit DNE According to the rule you mentioned, it means that the denominator will reach $0$ faster than numerator, so that the equation DNE as $(x,y)\to(0,0)$? $\endgroup$ –
- What is the symbol for undefined? - Mathematics Stack Exchange
$\begingroup$ @Shaun Thank you for pointing out about wheel theory I believe the staff at the Web site meant that in within the real complex number field, dividing any non-$0$ value by $0$ is usually considered to be undefined, while $0$ divided by $0$ is often called indeterminate
- calculus - When using the nth term test on a Alternating Series will it . . .
You need to learn not to treat "DNE" as if it is a legitimate mathematical object that interacts with things as numbers do, just as $\infty$ isn't either: how a limit equal to $\infty$ interacts with limit $0$ depends on the situation $\endgroup$
- limits - Convergence, divergence and existence - Mathematics Stack Exchange
Divergence means the limit doesn't exist "Divergence to $\infty$" is a special case of divergence, and we sometimes say that the limit exists in those cases, but strictly speaking it doesn't (unless we're working in the extended reals, which as far as I can tell is mostly done just to indulge in this specific abuse of terminology (yes, I know there are legitimate reasons to use them, I was
- calculus - Prove f is continuous and that f (0) DNE - Mathematics . . .
Prove f is continuous and that f'(0) DNE Ask Question Asked 9 years, 3 months ago
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