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- Question #33eb8 - Socratic
First, subtract #color (red) ($145)# from each side of the equation to isolate the #w# term while keeping the equation balanced:
- Question #5b826 - Socratic
What we're really doing here is that we're given an initial state with # ["BrCl"]_i = "0 050 M"#, and we're given #K_ (eq)#, which is defined for a final state we define as equilibrium, when the rate of the forward reaction is equal to that of the reverse reaction
- Two towns are 145 km apart. A bus leaves one of the towns . . . - Socratic
The car would travel 90 km in 1 hour, so it will travel 45 km in half an hour (30 min) The bus will travel 30 km They have traveled a total of 75 km of the 145 km between the towns, so there is 145-75=70 km between them
- The sum of the first nth term of a geometric series is 145 . . . - Socratic
The sum of the first nth term of a geometric series is 145 and the sum of the reciprocal is 145 33 The first term is 1 What is n and the common ratio? Precalculus
- Question #933a2 - Socratic
Solve: 1 sin x = 0 5623 2 cos x = 0 8963 3 tan x = -2 89 1 Calculator gives --> sin x = 0 5623 --> x = 34 22 and x = 180 - 34 22 = 145 78 deg Extended answers: x = 34 22 + k360 deg x = 145 78 + k360 deg 2 cos x = 0 8963 --> x = +- 26 32 deg Extended answers: x = +- 26 32 + k360 deg 3 tan x = -2 89 --> x = -70 93 and x = -70 93 + 180 = 109 09 deg Extended answers: x = 109 09 + k180 deg
- How do you solve \\frac { 1} { 5} y - \\frac { 29} { 14} = \\frac { 3 . . .
Explanation: To eliminate the fractions in the equation, multiply ALL terms on both sides by the #color (blue)"lowest common multiple"# (LCM) of 5 ,14 and 7, the values on the denominators
- A triangle has sides A, B, and C. The angle between sides A . . . - Socratic
The length of side A is 10 145 (3dp) The angle between sides A and B is _c= pi 8=180 8=22 5^0 The angle between sides B and C is _a= pi 12=180 12=15^0 Given C=15; A=?
- Can you help me with finding perimeter of this sector fragment?
Just Q8 I'll ask more questions if I need more help
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