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- Two towns are 145 km apart. A bus leaves one of the towns . . . - Socratic
The car would travel 90 km in 1 hour, so it will travel 45 km in half an hour (30 min) The bus will travel 30 km They have traveled a total of 75 km of the 145 km between the towns, so there is 145-75=70 km between them
- Question #33eb8 - Socratic
First, subtract #color (red) ($145)# from each side of the equation to isolate the #w# term while keeping the equation balanced:
- The sum of the first nth term of a geometric series is 145 . . . - Socratic
The sum of the first nth term of a geometric series is 145 and the sum of the reciprocal is 145 33 The first term is 1 What is n and the common ratio? Precalculus
- How do you solve \\frac { 1} { 5} y - \\frac { 29} { 14} = \\frac { 3 . . .
Explanation: To eliminate the fractions in the equation, multiply ALL terms on both sides by the #color (blue)"lowest common multiple"# (LCM) of 5 ,14 and 7, the values on the denominators
- Question #5b826 - Socratic
What we're really doing here is that we're given an initial state with # ["BrCl"]_i = "0 050 M"#, and we're given #K_ (eq)#, which is defined for a final state we define as equilibrium, when the rate of the forward reaction is equal to that of the reverse reaction
- Question #509cd - Socratic
196 ft ^2 Refer to figures below From the given data we have D_1=6 ft => r_1=3ft D_2=4 fl => r_2=2ft h=12ft As we can see in Fig (a) r_2 (H-h)=r_1 H 2 (H-12)=3 H => 2H=3H-36 => H=36 Since s=sqrt(2)*r (see Fig (b)) s_1=3sqrt(2) s_2=2sqrt(2 Area of bases S_(b1)=s_1^2=(3sqrt(2))^2=18 S_(b2)=s_2^2=(2sqrt(2))^2=8 Side of the slanted trapezoid (see Fig (c)) x^2=h^2+(r_1-r_2)^2 x=sqrt(12^2+1^2
- An isosceles triangle has sides A, B, and C, such that sides . . . - Socratic
12 04 (approx) Let the length of side A or B = x and base is 16 So the height is sqrt [x^2 - (16 2)^2] Now the area of triangle = 1 2 * base * height = 1 2 * 16 * sqrt [x^2 - (16 2)^2] Therefore, 1 2 * 16 * sqrt [x^2 - (16 2)^2] = 72 or, sqrt [x^2 - 8^2]=72 8 or, x^2 - 64 = 81 or, x^2 = 145 or, x = sqrt 145 = 12 04 (approx)
- Solve # { (sqrtx (1-4x-y)=2), (sqrty (1+4x+y)=6):}# - Socratic
No real solutions Calling alpha = 4x+y we have { (sqrtx (1-alpha)=2), (sqrty (1+alpha)=6):} then 2 alpha = (1+alpha)^2- (1-alpha)^2=36 y-4 x or 4x+y = 9 y-1 x we
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