Difference between 0 and 0u - Stack Overflow The uint type is 32-bit unsigned integer type Its default value is the number 0u or 0U (the two are equivalent) The 'u' letter indicates that the number is of type uint (otherwise it is understood as int) Then is there a difference between 0 and 0u? If not, then why is the default value '0u' What is the advantage of suffixing an integer
c - What does u mean after a number? - Stack Overflow But, be aware that changing signedness can lead to different behavior in various contexts, for example: (x > 0) can (depending on the type of x) mean something different than (x > 0u) Luckily, the compiler code checker will typically warn you about suspicious cases Nevertheless, adding a u suffix should be done with consideration
c - What do 0LL or 0x0UL mean? - Stack Overflow I am reading the Google Go tutorial and saw this in the constants section: There are no constants like 0LL or 0x0UL I tried to do a Google search but all that comes up are instances where people
c - Why (uint8)0U appears to the static code analysis tool as a . . . 0U has type unsigned int and (uint8)0U has type unsigned char, but like all types smaller than int, it gets promoted to int in an expression context such as an operand to ~ You should just remove the cast and use ~0U Note however that on systems with 16- or 32-bit ints using two's complement representation (almost all current systems *): ~0U has type unsigned int and evaluates to 0xFFFFFFFF